Question

calcular!!!!

Un tercio de la suma entre - 7/3 y 1 1/4​

Answer 1

Hola! :3

Resolvemos:

$(\frac{1}{3} )(\frac{-7}{3}+1\frac{1}{4} )$

$(\frac{1}{3})(\frac{-7}{3}+\frac{5}{4})$

$(\frac{1}{3})( \frac{(-7)(4)+(3)(5)}{(3)(4)})$

$(\frac{1}{3})(\frac{-28+15}{12} )$

$(\frac{1}{3} )(\frac{-13}{12} )$

$\frac{(1)(-13)}{(3)(12)}$

$\frac{-13}{36}$

El resultado es -13/36

Espero haberte ayudado :D