Question

calcular las ´potencias (1/9 + i)²

Answer 1

Utiliza el binomio al cuadrado,

(a + b) ² = a² + 2ab + b²

$( \frac{1}{9} + i )^{2} = (\frac{1}{9})^{2} + \frac{2i}{9} + i^{2} \\ \\ ( \frac{1}{9} + i )^{2} = \frac{1}{81} + \frac{2i}{9} - 1 \\ \\ \boxed{( \frac{1}{9} + i )^{2} = \frac{2i}{9} - \frac{80}{81} }$


Salu2 :).