Calcular la temperatura en grados centígrados del N2 a 358 mmhg 250 ML y 3.5 kg
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Mm N2 = 28 g/mol
P = 358 mmHg
1 atm ----- 760 mmHg
x ---- 358 mmHg
x = 0.471 atm.
V = 250 / 1000 = 0.25 L
n = masa /Mm
m = 3.5 x 1000 = 3500 g
n = 3500 g / 28 g/mol
n = 125 mol
R = 0.0821 (atm L / mol K)
P x V = n x R x T
T = P x V
````````
n x R
T = 0.471 Atm. 0.250 L
``````````````````````````
125 mol x 0.0821(atm L/molK)
T = 0.0115 K
ºC = K - 273
ºC = 0.0115 - 273 = -272.98 ºC
P = 358 mmHg
1 atm ----- 760 mmHg
x ---- 358 mmHg
x = 0.471 atm.
V = 250 / 1000 = 0.25 L
n = masa /Mm
m = 3.5 x 1000 = 3500 g
n = 3500 g / 28 g/mol
n = 125 mol
R = 0.0821 (atm L / mol K)
P x V = n x R x T
T = P x V
````````
n x R
T = 0.471 Atm. 0.250 L
``````````````````````````
125 mol x 0.0821(atm L/molK)
T = 0.0115 K
ºC = K - 273
ºC = 0.0115 - 273 = -272.98 ºC
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