Question

calcular la raiz de : a)³√-3125=
b)³√16=

Answer 1

Respuesta:

-5$\sqrt[3]{25}$

b)18

Answer 2

a)

$\sqrt[3]{-3125}\\=-\sqrt[3]{3125}\\3125=5^5\\=-\sqrt[3]{5^5}\\=-\sqrt[3]{5^3\cdot \:5^2}\\=-\sqrt[3]{5^3}\sqrt[3]{5^2}\\\sqrt[3]{5^3}=5\\=-5\sqrt[3]{5^2}\\=-5\sqrt[3]{25}$

b)

$\sqrt[3]{16}\\16= 2^4\\=\sqrt[3]{2^4}\\=\sqrt[3]{2^3\cdot \:2}\sqrt[3]{2^3\cdot \:2}\\=\sqrt[3]{2^3}\sqrt[3]{2}\\\sqrt[3]{2^3}=2\\=2\sqrt[3]{2}$