calcular la normalidad de 20.5 g de carbonato sodico en 0.5 litros de solucion
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Mm Na2CO3 = 105.9 g/mol
Peq = 105.9 g/mol /2 = 52.95 g/eq.
eq. = masa/Peq.
eq. = 20.5 g/ 52.95g/eq
eq. = 0.387
N = eq. / V(L)
N = 0.387 eq. / 0.5 L
N = 0.774 eq/L
Peq = 105.9 g/mol /2 = 52.95 g/eq.
eq. = masa/Peq.
eq. = 20.5 g/ 52.95g/eq
eq. = 0.387
N = eq. / V(L)
N = 0.387 eq. / 0.5 L
N = 0.774 eq/L
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