Química, pregunta formulada por churululo123, hace 1 año

calcular la masa molecular de los siguientes compuestos
a) H3BO3
b) AL2(SO4)3
c) H3PO3
d) H2CO3
e) HNO3
f) C6H1206


Doy 20 puntos pero aurita
Por favor es urgente

que p**** van a responder



Respuestas a la pregunta

Contestado por snorye
65
H3BO3

H: 3 x 1 = 3 g/mol
B: 1 X 10.8 = 10.8 g/mol
O: 3 x 16 = 48 g/mol
``````````````````` `````````````
           Mm = 61.8  g/mol

H2CO3

H: 2x 1 = 2 g/mol
C: 1 X 12 = 12 g/mol
O: 3 x 16 = 48 g/mol
``````````````````` `````````````
         Mm = 62  g/mol

AL2(SO4)3

Al: 2 x 27 = 54 g/mol
S: 3 x  32 = 96 g/mol
O: 12 x 16 = 192 g/mol
````````````````````````````````
         Mm = 342 g/mol

H3PO3

H: 3 x  1 = 3 g/mol
P: 1 x  31 = 31 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
         Mm = 82 g/mol

HNO3

H: 1 x1 = 1 g/mol
N: 1 x 14 = 14 g/mol
O: 3 x 16 = 48 g/mol
``````````````````````````````
         Mm = 63 g/mol


C6H12O6

C: 6 x 12 = 72 g/mol
H: 12  x 1 = 12 g/mol
O:  6 x 16 = 96 g/mol
``````````````````````````````````
         Mm = 180 g/mol



churululo123: gracias mi amigo
Contestado por jhonny773
16

Respuesta:

H3BO3

H: 3 x 1 = 3 g/mol

B: 1 X 10.8 = 10.8 g/mol

O: 3 x 16 = 48 g/mol

``````````````````` `````````````

          Mm = 61.8  g/mol

H2CO3

H: 2x 1 = 2 g/mol

C: 1 X 12 = 12 g/mol

O: 3 x 16 = 48 g/mol

``````````````````` `````````````

        Mm = 62  g/mol

AL2(SO4)3

Al: 2 x 27 = 54 g/mol

S: 3 x  32 = 96 g/mol

O: 12 x 16 = 192 g/mol

````````````````````````````````

        Mm = 342 g/mol

H3PO3

H: 3 x  1 = 3 g/mol

P: 1 x  31 = 31 g/mol

O: 3 x 16 = 48 g/mol

````````````````````````````````

        Mm = 82 g/mol

HNO3

H: 1 x1 = 1 g/mol

N: 1 x 14 = 14 g/mol

O: 3 x 16 = 48 g/mol

``````````````````````````````

        Mm = 63 g/mol

C6H12O6

C: 6 x 12 = 72 g/mol

H: 12  x 1 = 12 g/mol

O:  6 x 16 = 96 g/mol

``````````````````````````````````

        Mm = 180 g/mol

Explicación:

H3BO3

H: 3 x 1 = 3 g/mol

B: 1 X 10.8 = 10.8 g/mol

O: 3 x 16 = 48 g/mol

``````````````````` `````````````

          Mm = 61.8  g/mol

H2CO3

H: 2x 1 = 2 g/mol

C: 1 X 12 = 12 g/mol

O: 3 x 16 = 48 g/mol

``````````````````` `````````````

        Mm = 62  g/mol

AL2(SO4)3

Al: 2 x 27 = 54 g/mol

S: 3 x  32 = 96 g/mol

O: 12 x 16 = 192 g/mol

````````````````````````````````

        Mm = 342 g/mol

H3PO3

H: 3 x  1 = 3 g/mol

P: 1 x  31 = 31 g/mol

O: 3 x 16 = 48 g/mol

````````````````````````````````

        Mm = 82 g/mol

HNO3

H: 1 x1 = 1 g/mol

N: 1 x 14 = 14 g/mol

O: 3 x 16 = 48 g/mol

``````````````````````````````

        Mm = 63 g/mol

C6H12O6

C: 6 x 12 = 72 g/mol

H: 12  x 1 = 12 g/mol

O:  6 x 16 = 96 g/mol

``````````````````````````````````

        Mm = 180 g/mol

Pregunta anterior
Siguiente pregunta
Otras preguntas
Filosofía, hace 8 meses
acento hace referencia a la silaba fuerte en la palbra verdero o falso​...
Matemáticas, hace 8 meses
Pagina 92 de matemáticas que va con la pagina 159 del libro recortable ayuda es para hoy...
Educ. Fisica, hace 8 meses
-¿ Cuál es el objetivo de este juego deportivo? ¿cómo se gana un punto o tanto? Fútbol​...
Matemáticas, hace 1 año
Cual es el suplemento de un angulo, si su complementario es 35º?
Matemáticas, hace 1 año
ayuda ayuda la suma,la diferencia y el producto de dos numeros estan en la misma relacion que los numeros 11, 3 y 560. hallar uno de los numeros.
Química, hace 1 año
la fusion de hielo corresponde a un cambio quimico...
Matemáticas, hace 1 año
ejemplos de la variable cualitativa.
Historia, hace 1 año
Que pretende comunicar el autor car el autor en el poema la flecha de oro...