Question

Calcular el volumen ocupado, en c.n por 0.35 moles de CH4 (gas metano).

Answer 1

Calcular el volumen ocupado, en c.n por 0.35 moles de CH4 (gas metano).

         1 mol   -----   22.4 L

   0.35 mol   -----      x

            x = 7.84 litros de CH4

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T = 273 K

P = 1 atm

n = 0.35 moles

V = ?

R = 0.0821 (L atm/mol K)

Aplicar la ley de los gases ideales

V x P = n x R x T

V =  (0.35 mol  x   0.0821 (L atm/mol K)  x  273 K) / 1 atm

V = 7.84 Litros de CH4