Question

Calcular el perímetro del cuadrado cuya diagonal mide 7,60 dm.​

Answer 1

Teorema de Pitagoras

(7,60 dm)² = L² + L²

(7,60 dm)² = 2L²

57,76 dm² = 2L²

57,76 dm²/2 = L²

28,88 dm² = L²

$\sqrt{28,88dm^{2} } = \sqrt{L^{2} } \\\\5,27 dm= L$

Eternamente axllxa