Question

-Calcular
A) (2+5i) (3+4i)= (soluc -14+23i)
B) (1+3i) (1+i)= (soluc -2+4i)
C) ( 1+i) (-1-i)= (soluc -2i)
D) (2-5i) i=. (soluc 5+2i)
E) (2+5i) (2-5i)=. (soluc 29)
​

Answer 1

Explicación paso a paso:

A) (2+5i) (3+4i)= (soluc -14+23i)

(2+5i) (3+4i)

(2)(3)+(2)(4i)+(5i)(3)+(5i)(4i)

6 +8i +15i +20i²

6 + 23i + 20(-1)

6 + 23i - 20

6 - 20+ 23i

-14+23i

B) (1+3i) (1+i)= (soluc -2+4i)

(1+3i) (1+i)

(1)(1)+(1)(i)+(3i)(1)+(3i)(i)

1 + i +3i + 3i²

1 +4i + 3i²

1 +4i + 3(-1)

1 +4i -3

1 -3+4i

-2+4i

C) ( 1+i) (-1-i)= (soluc -2i)

( 1+i) (-1-i)

(1)(-1)+(1)(-i)+(i)(-1)+(i)(-i)

-1 - i -i -i²

-1 -2i - i²

-1 -2i - (-1)

-1 -2i +1

-1 +1-2i

2i

D) (2-5i) i=. (soluc 5+2i)

(2-5i) i

2i - 5i²

2i -5(-1)

2i +5

5 + 2i

E) (2+5i) (2-5i)=. (soluc 29)

(2+5i) (2-5i)

(2)(2)+(2)(-5i)+(5i)(2)+(5i)(-5i)

4 -10i +10i -25i²

4-25i²

4 -25(-1)

4+25

29