Question

Calcula las siguientes sumatorias.

Answer 1

Respuesta:

Explicación:

∑₀¹ k+1/k²+1

=(0+1/0+1)+(1+1/1+1)+(2+1/4+1)+(3+1/9+1)

=1/1 +2/2 +3/5 +4/10

=1+1+3/5+2/5

=1+1+5/5

=1+1+1

=3

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∑⁵   (2i²-4i-6)

i =₁

=(2(1)-4(1)-6)+(2(4)-4(2)-6)+(2(9)-4(3)-6)+(2(16)-4(4)-6)+(2(25)-4(5)-6)

=(2-4-6)+(8-8-6)+(18-12-6)+(32-16-6)+(50-20-6)

=-8-6+0+10+24

=-14+34

=20