calcula la fraccion molar (x) de una solucion solida. de 150 gramos de Fe en 250 gramos de Cu
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Mm Fe = 55.85 g/mol
Cu = 63.54 g/mol
mol = masa / Mm
mol Fe = 150 g / 55.85 g/mol = 2.685 mol
mol Cu = 250 g / 63.54 g/mol = 3.935
ntotal = n soluto + n solvente
n total = 2.685 mol + 3.935 mol = 6.62 mol
X soluto = n soluto
````````````
n total
X soluto = 2.685 mol
``````````````
6.62 mol
X soluto = 0.406
X solvente = n solvente
````````````````
n total
X solvente = 3.935 mol
````````````````
6.62 mol
X solvente = 0.60
Cu = 63.54 g/mol
mol = masa / Mm
mol Fe = 150 g / 55.85 g/mol = 2.685 mol
mol Cu = 250 g / 63.54 g/mol = 3.935
ntotal = n soluto + n solvente
n total = 2.685 mol + 3.935 mol = 6.62 mol
X soluto = n soluto
````````````
n total
X soluto = 2.685 mol
``````````````
6.62 mol
X soluto = 0.406
X solvente = n solvente
````````````````
n total
X solvente = 3.935 mol
````````````````
6.62 mol
X solvente = 0.60
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