calcula la composición centesimal del nitrato de sodio NaNO3...ayuda porfa
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Mm NaNO3
Na: 1 x 23 = 23 g/mol
N: 1 x 14 = 14 g/mo
O: 3 x 16 = 48 g/mol
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Mm = 85 g/mol
Na:
85 g ------ 100 %
23 g ------- x
x = 27.05 %
N:
85 g ---- 100 %
14 g ----- x
x = 16.47 %
O:
85 g ---- 100 %
48 g ----- x
x = 56.47 %
Na: 1 x 23 = 23 g/mol
N: 1 x 14 = 14 g/mo
O: 3 x 16 = 48 g/mol
````````````````````````````````````
Mm = 85 g/mol
Na:
85 g ------ 100 %
23 g ------- x
x = 27.05 %
N:
85 g ---- 100 %
14 g ----- x
x = 16.47 %
O:
85 g ---- 100 %
48 g ----- x
x = 56.47 %
paulcp:
Graicas
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