calcula la composición centesimal del nitrato de sodio NaNO3...ayuda porfa
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Mm NaNO3
Na: 1 x 23 = 23 g/mol
N: 1 x 14 = 14 g/mol
O: 3 x 16 = 48 g/mol
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Mm = 85 g/mol
SODIO
85 g ----- 100 %
23 g ----- x
x = 27.05 % Na
NITROGENO
85 g ---- 100 %
14 g ---- x
x = 16.47 % N
OXIGENO
85 g ----- 100 %
48 g ---- x
x = 56.47 % O
Na: 1 x 23 = 23 g/mol
N: 1 x 14 = 14 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
Mm = 85 g/mol
SODIO
85 g ----- 100 %
23 g ----- x
x = 27.05 % Na
NITROGENO
85 g ---- 100 %
14 g ---- x
x = 16.47 % N
OXIGENO
85 g ----- 100 %
48 g ---- x
x = 56.47 % O
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