Question

Calcula el volumen de dioxido de carbono que se desprendera al quemar 1kg de butano C4H10 en condiciones normales

Answer 1

                      C4H10  +  13/2 O2  →    4CO2  +   5H2O

Mm C4H1O = 58 g/mol

1Kg = 1000 g de C4H10

1. calcular moles de C4H1O

mol C4H1O =  1000 g  x  1  mol
                                       `````````````
                                          58 g

mol C4H1O = 17.24

2. Calcular moles de CO2

mol CO2 = 17.24 mol C4H10  x  4 mol CO2
                                                   ````````````````
                                                    1 mol C4H10

mol CO2 = 68.96

3. calcular litros de CO2

       1 mol ------ 22.4 L
68.96 mol ------     x

x = 68.96 mol  x  22.4 L
     ````````````````````````````
                 1 mol

x = 1544.704 Litros de CO2