Question

Calcula el limite de
Lim=0 (3 x^3 -6x^2)/(2x^4-15 x^2)
Linm=1 (x^2 -2×+1)/(x^2-3x+2)
Lim=2 (x^5+ 9x^2)/ (x4-3x^2)

Answer 1

Respuesta:

1) 2/5

2) 0

3) 17

Explicación paso a paso:

1) Lim x →0   (3x³ -6x²)/(2x⁴-15 x²) =

Lim x→0  3x².(x - 2)/x² .(2x² - 15) =

Lim x→0  3.(x - 2)/(2x² - 15) = 3.( 0-2)/(2.0² - 15)  = 3.(-2)/-15 = -6/-15 = 2/5          

2) Lim x→1 (x² - 2x + 1)/(x² - 3x + 2) =

Lim x→1  (x - 1)²/ (x-2)(x-1) =

Lim x→1  (x-1)/(x-2) = (1-1)/(1-2) = 0/-1 = 0

3) Lim x→2  (x⁵ + 9x²)/(x⁴ - 3x²) =

Lim x→2  x²(x³ + 9)/x²(x² - 3) =

Lim x→2  (x³ + 9)/(x² - 3) = (2³ + 9)/(2² - 3) = 17/1 = 17