Question

CALCULA EL CUADRADO DE LOS SIGUIENTES BINOMIOS EN TU CUADERNO


SE CALCULA CON LA SIGUIENTE FORMULA

(a+b)^2= a^2+2ab+b^2


(x+1)^2
(2x-y)^2
(z^3-7)^2
(-h+1/2)^2
(x-1)^2
(-x-3y)^2
(x^2-2)^2
(2m-1/4)^2
(-m+3)^2
(r+0.1)^2
(-x-0.5)^2
(a+1/10)^2

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Answer 1

Cuadrado de los Binomios

Fórmula

$\bold{(a+b)^2= a^2 + 2ab + b^2}\\\\Entonces \\\\\\ \bold{(x+1)^2= x^2 + 2(x)(1)+ (1)^2= \boxed{x^2+2x+1}} \\\\ \bold{(2x-y)^2= (2x)^2 + 2(2x)(-y)+ (-y)^2= \boxed{4x^2-4xy+y^2}} \\\\ \bold{(z^3-7)^2= (z^3)^2 + 2(z^3)(-7)+ (-7)^2= \boxed{z^6-14z^3+49}}$

$\bold{(-h+\frac{1}{2})^2= (-h)^2 + 2(-h)(\frac{1}{2})+ (\frac{1}{2})^2= \boxed{h^2-h+\frac{1}{4}}} \\\\ \bold{(x-1)^2= (x)^2 + 2(x)(-1)+ (-1)^2= \boxed{x^2-2x+1}}\\\\ \bold{(-x+-3y)^2= (-x)^2 + 2(-x)(-3y)+ (-3y)^2= \boxed{x^2+6xy+9y^2}} \\\\ \bold{(x^2-2)^2= (x^2)^2 + 2(x^2)(-2)+ (-2)^2= \boxed{x^4-4x^2+4}}$

$\bold{(2m-\frac{1}{4})^2= (2m)^2 + 2(2m)(-\frac{1}{4})+ (-\frac{1}{4})^2= \boxed{4m^2-m+\frac{1}{16}}}\\\\ \bold{(-m+3)^2= (-m)^2 + 2(-m)(3)+ (3)^2= \boxed{m^2-6m+9}} \\\\\bold{(r+0,1)^2= (r)^2 + 2(r)(0,1)+ (0,1)^2= \boxed{r^2+0,2r+0,01}}\\\\ \bold{(-x-0,5)^2= (-x)^2 + 2(-x)(0,5)+ (0,5)^2= \boxed{x^2-x+0,25}}\\\\ \bold{(a+\frac{1}{10})^2= (a)^2 + 2(a)(\frac{1}{10})+ (\frac{1}{10})^2= \boxed{a^2+\frac{1}{5}a+\frac{1}{100}}}$

Espero que te sirva, salu2!!!!