Question

Calcula: E= sec²θ porfavorr​

Answer 1

Pitágoras

${n}^{2} = {1}^{2} + { \sqrt{2} }^{2} \\ {n}^{2} = 1 + 2 \\ n = \sqrt{3}$

Nos pide sec²θ

$sec²θ = ( \frac{ \sqrt{3} }{ \sqrt{2} } )^{2} = \frac{3}{2}$

• sec²θ es 3/2