Question

¿Calcula cuando venderia el días 30? 5;10;15;20;......
(aplicando caluculo de término enésimo)

Ayuda pliss ​

Answer 1

Determinamos el término n-ésimo, por ello usaremos:

           $\begin{array}{c}\begin{array}{c}\boldsymbol{\boxed{\hphantom{A}\underset{\vphantom{.}}{\overset{\vphantom{A}}{\sf{a_n = a_1 + (n-1)r}}}\hphantom{A}}}\end{array}\\\\\begin{array}{c}\sf{Donde}\end{array}\\\\\begin{array}{llllllllll}\sf{\circledast\quad a_n:T\acute{e}rmino\ general}&&&&&&&&&\sf{\circledast\quad a_1:Primer\ t\acute{e}rmino}\\&\\\sf{\circledast\quad n:N^{\circ}\ de\ t\acute{e}rminos}&&&&&&&&&\sf{\circledast\quad r:Raz\acute{o}n}\end{array}\end{array}$

Del problema tenemos que:

                   $\begin{array}{c}\sf{\underset{\displaystyle\underset{\displaystyle a_1}{\downarrow}}{5},\quad10,\quad15,\quad20,...} \\\\\begin{array}{ccccccccccccccccc}\circledast\quad\sf{a_1=5}&&&&&&&&&&&&&&&&\circledast\quad\sf{r=5}\end{array}\end{array}$

Reemplazamos

                                                $\begin{array}{c}\sf{a_n=a_1+(n-1)r}\\\\\sf{a_n=5+\left(n-1\right)\left(5\right)}\\\\\sf{a_n=5+\left(5n-5\right)}\\\\\boxed{\boldsymbol{\sf{a_n=5n}}}\\\\\end{array}$

Nos pide el día 30, es decir, n = 30, entonces

                                                       $\begin{array}{c}\sf{a_n = 5\,n}\\\\\sf{a_n = 5\,(30)}\\\\\boxed{\boldsymbol{\sf{a_n = 150}}}\end{array}$

Rpta. El día 30 venderá 150.

                                              $\boxed{\sf{{R}}\quad\raisebox{10pt}{ \sf{\red{O}} }\!\!\!\!\raisebox{-10pt}{ \sf{\red{O}} }\quad\raisebox{15pt}{ \sf{{G}} }\!\!\!\!\raisebox{-15pt}{ \sf{{G}} }\quad\raisebox{15pt}{ \sf{\red{H}} }\!\!\!\!\raisebox{-15pt}{ \sf{\red{H}} }\quad\raisebox{10pt}{ \sf{{E}} }\!\!\!\!\raisebox{-10pt}{ \sf{{E}} }\quad\sf{\red{R}}}\hspace{-64.5pt}\rule{10pt}{.2ex}\:\rule{3pt}{1ex}\rule{3pt}{1.5ex}\rule{3pt}{2ex}\rule{3pt}{1.5ex}\rule{3pt}{1ex}\:\rule{10pt}{.2ex}$

Answer 2

Respuesta:

a30 = 150

Explicación paso a paso:

5,10,15,20

So, a1 = 5, d = 10-5 = 5

Now, Using the formula an = a1+(n-1)d, we have

a30 = 5+(30-1)5

a30 = 5 + 29*5

a30 = 5 + 145

a30 = 150

So, the 30th term will be 150.