Question

Calcula 3/2+√125/8-(-3/5)÷1/2
​

Answer 1

Respuesta:

$mathbf{3/2+\sqrt{125}/8-(-3/5)÷1/2=\frac{21}{5}+\frac{5\sqrt{5}}{4}}$

Explicación paso a paso:

$3/2+\sqrt{125}/8-(-3/5)÷1/2=\frac{\frac{3}{2}+\frac{\sqrt{125}}{8}-\left(-\frac{3}{5}\right)}{\frac{1}{2}}$

$\sqrt{125}=\sqrt{(5)(25)}=\sqrt{5}\sqrt{25}=5\sqrt{5}$

$-\left(-\frac{3}{5}\right)=\frac{3}{5}$

Simplificando:

$frac{\frac{3}{2}+\frac{\sqrt{125}}{8}-\left(-\frac{3}{5}\right)}{\frac{1}{2}}=\frac{\frac{3}{2}+\frac{5\sqrt{5}}{8}+\frac{3}{5}}{\frac{1}{2}}=\\\\=\frac{\frac{60+25\sqrt{5}+24}{40}}{\frac{1}{2}}=\\\\=\frac{\frac{84+25\sqrt{5}}{40}}{\frac{1}{2}}=\frac{(2)\left(84+25\sqrt{5}}{(40)(1)}=\\\\=\frac{168+50\sqrt{5}}{40}=\frac{21}{5}+\frac{5\sqrt{5}}{4}$