Question

calacula la composision porcentual de cada elemento que forma una molecula de acido sulfurico H2SO4 HNO3 y Na2SO4

Answer 1

H2SO4

Mm H: 2 x 1 = 2 g/mol
       S: 1 x 32 g = 32 g/mol
       O: 4 x 16 =  64 g/mol
         ````````````````````````````````
                     Mm = 98 g/mol

H 
98 g ----- 100 %
 2 g -----    X
x = 2.04 %

S:
98 g ----- 100 %
32  g -----    X
x = 32.65 %

O:
98 g ----- 100 %
64  g -----    X
x =65.30 %

HNO3
Mm H: 1 x 1 = 1 g/mol
       N: 1 x 14 g = 32 g/mol
       O: 3 x 16 =  48 g/mol
         ````````````````````````````````
                     Mm = 63 g/mol

H:
63 g ----- 100 %
  1  g -----    X
x = 1.58 %

N:
63 g ----- 100 %
14  g -----    X
x = 22.22%

O:
63 g ----- 100 %
48  g -----    X
x = 76.19%

Na2SO4

Mm Na:  2 x 23 = 46 g/mol
        S: 1 x 32 = 32 g/mol
        O: 4 x 16 = 64 g/mol
   ``````````````````````````````````````
           Mm = 142 g/mol

Na:
142 g ----- 100 %
 46 g -----    X
x =  32.39 %

S:
142 g ----- 100 %
 32  g -----    X
x =  22.53 %

O:
142 g ----- 100 %
 64 g -----    X
x =  45.07 %