Question

c) (9x(29 - 6x4) - 7x[20 - (6 + 3x4)-- {8x5 - [15x3 - (12 + 7x)]x(21 - 9x2)) =​

Answer 1

$\huge\red {\mid {\fbox{\tt {Hola}}\mid}}$

(9x(29 - 6x4) - 7x[20 - (6 + 3x4)-- {8x5 - [15x3 - (12 + 7x)]x(21 - 9x2)) =

=9(29−24)−7(20−(6+(3)(4))−((8)(5)−((15)(3)−(12+7))(21−(9)(2))))

=(9)(5)−7(20−(6+(3)(4))−((8)(5)−((15)(3)−(12+7))(21−(9)(2))))

=45−7(20−(6+(3)(4))−((8)(5)−((15)(3)−(12+7))(21−(9)(2))))

=45−7(20−(6+12)−((8)(5)−((15)(3)−(12+7))(21−(9)(2))))

=45−7(20−18−((8)(5)−((15)(3)−(12+7))(21−(9)(2))))

=45−7(2−((8)(5)−((15)(3)−(12+7))(21−(9)(2))))

=45−7(2−(40−((15)(3)−(12+7))(21−(9)(2))))

=45−7(2−(40−(45−(12+7))(21−(9)(2))))

=45−7(2−(40−(45−19)(21−(9)(2))))

=45−7(2−(40−26(21−(9)(2))))

=45−7(2−(40−26(21−18)))

=45−7(2−(40−(26)(3)))

=45−7(2−(40−78))

=45−7(2−(−38))

=45−(7)(40)

=45−280

=−235