Question

c=40%h=6.71%pm=182g/mol​

Answer 1

Respuesta:

FE: CH2O

FM: (CH2O)6 = C6H12O6

Explicación:

C = 40% H = 6.71% O = 53.29 %

Pm = 182g/mol​

1. calcular moles

n C: 40 g / 12 g/mol = 3.33

n H: 6.71 g / 1 g/mol = 6.71 mol

n O: 53.29 g / 16 g/mol = 3.33 mol

2. dividir entre el menor de los resultados

C: 3.33 mol / 3.33 mol = 1

H: 6.71 mol / 3.33 mol = 2

O: 3.33 mol / 3.33 mol = 1

3. FE: CH2O

4. calcular Mm de la  FE

C: 1 x 12 = 12 g/mol

H: 2 x 1 = 2 g/mol

O: 1 x 16  = 16 g/mol

     Mm = 30 g/mol

5. calcular factor n

n = Mm compuesto / Mm FE

n = 180 g/mol / 30 g/mol

n = 6

6. FM: (CH2O)6 = C6H12O6