Question

bir solo Rasgos de una mentalidad auto centrada Coloca en el espacio que se encuentra arriba de cada enunciado, una palabra con la que calificarías la acción que se describe el enunciado.​

Answer 1

Respuesta:

Explicación:

$\begin{array}{cccccc}\overset{\boldsymbol{\sf{Para\ x = -3}}}{\begin{array}{c}\sf{\vphantom{\rule{10pt}{25pt}}y=\dfrac{x}{16}-\dfrac{3}{16}}\\\\\sf{y=\dfrac{\left(-3\right)}{16}-\dfrac{3}{16}}\\\\\boxed{\boldsymbol{\sf{y=-\dfrac{3}{8}}}}\end{array}}&\overset{\boldsymbol{\sf{Para\ x = -2}}}{\begin{array}{c}\sf{\vphantom{\rule{10pt}{25pt}}y=\dfrac{x}{16}-\dfrac{3}{16}}\\\\\sf{y=\dfrac{\left(-2\right)}{16}-\dfrac{3}{16}}\\\\\boxed{\boldsymbol{\sf{y=-\dfrac{5}{16}}}}\end{array}}\\\overset{\boldsymbol{\sf{Para\ x = -1}}}{\begin{array}{c}\sf{\vphantom{\rule{10pt}{25pt}}y=\dfrac{x}{16}-\dfrac{3}{16}}\\\\\sf{y=\dfrac{\left(-1\right)}{16}-\dfrac{3}{16}}\\\\\boxed{\boldsymbol{\sf{y=-\dfrac{1}{4}}}}\end{array}}&\overset{\boldsymbol{\sf{Para\ x = 0}}}{\begin{array}{c}\sf{\vphantom{\rule{10pt}{25pt}}y=\dfrac{x}{16}-\dfrac{3}{16}}\\\\\sf{y=\dfrac{\left(0\right)}{16}-\dfrac{3}{16}}\\\\\boxed{\boldsymbol{\sf{y=-\dfrac{3}{16}}}}\end{array}}\\\overset{\boldsymbol{\sf{Para\ x = 1}}}{\begin{array}{c}\sf{\vphantom{\rule{10pt}{25pt}}y=\dfrac{x}{16}-\dfrac{3}{16}}\\\\\sf{y=\dfrac{\left(1\right)}{16}-\dfrac{3}{16}}\\\\\boxed{\boldsymbol{\sf{y=-\dfrac{1}{8}}}}\end{array}}&\overset{\boldsymbol{\sf{Para\ x = 2}}}{\begin{array}{c}\sf{\vphantom{\rule{10pt}{25pt}}y=\dfrac{x}{16}-\dfrac{3}{16}}\\\\\sf{y=\dfrac{\left(2\right)}{16}-\dfrac{3}{16}}\\\\\boxed{\boldsymbol{\sf{y=-\dfrac{1}{16}}}}\end{array}}\\\overset{\boldsymbol{\sf{Para\ x = 3}}}{\begin{array}{c}\sf{\vphantom{\rule{10pt}{25pt}}y=\dfrac{x}{16}-\dfrac{3}{16}}\\\\\sf{y=\dfrac{\left(3\right)}{16}-\dfrac{3}{16}}\\\\\boxed{\boldsymbol{\sf{y=0}}}\end{array}}&\end{array}$