Question

binomios con un término común. 1) (x+4)(x+2)=. 2)(m-3)(m-7)=. 3)(y+9)(y-2)=. 4)(a+2)(a-5)=. 5)(3m+2)(3m+5)=​

Answer 1

Explicación paso a paso:

$1) \\ (x + 4)(x + 2) \\ {x}^{2} + 2x + 4x + 8 \\ {x}^{2} + 6x + 8 \\ \\ 2) \\ (m - 3)(m - 7) \\ {m}^{2} - 7m - 3m + 21 \\ {m}^{2} - 10m + 21 \\ \\ 3) \\ (y + 9)(y - 2) \\ {y}^{2} - 2y + 9y - 18 \\ {y}^{2} + 7y - 18 \\ \\ 4) \\ (a + 2)(a - 5) \\ {a}^{2} - 5a + 2a - 10 \\ {a}^{2} - 3a - 10 \\ \\ 5) \\ (3m + 2)(3m + 5) \\ {9m}^{2} + 15m + 6m + 10 \\ {9m}^{2} + 21m + 10$