Question

binomios al cubo
(n-4)3

(2x+1)3

(1-3y)3

ayuda :(​

Answer 1

Respuesta:

n-4 × n-4 = n^2+16

n^2+16 × n-4 = n^3-64

2x+1 × 2x+1 = 4x^2+1

4×^2+1 × 2x+1 = 8x^3+1

1-3y × 1-3y = 1+9y^2

1+9y^2 × 1-3y = 1-27y^3

Gracias