Question

B={xER/x²+x-6=0}

A={2,-3}
es iguales o disjuntas​

Answer 1

Respuesta:

Exact result:

B = ((e R)/x + x - 6 = 0)

Solutions:

x = 3 - sqrt(9 - e R), 3 - sqrt(9 - e R)!=0

x = sqrt(9 - e R) + 3, sqrt(9 - e R) + 3!=0

Solution:

R = 9/e, x = 3

Integer solution:

R = 0, x = 6

Respuesta:

Difference:

-3 - 2 = -5

Ratio:

-2/3 = -2/3≈-0.666667

Arithmetic comparison:

-3<2 and 2>-3  

Total:

2 - 3 = -1

Vector length:

sqrt(13)

Normalized vector:

(2/sqrt(13), -3/sqrt(13))

Angles between vector and coordinate axes:

horizontal: cos^(-1)(2/sqrt(13)) | vertical: cos^(-1)(-3/sqrt(13))

Polar coordinates:

r≈3.60555 (radius), θ≈-56.3099° (angle)

no se que son pero espero te sirvan :)