Question

b. Si f(x) = x^3 + 2x^2 – 3, determine f(0),f(3), f(-3)​

Answer 1

Respuesta:

$f(x)=x^3+2x^2-3$

$f(0)=(0)^3+2(0)^2-3=0+0-3=-3$

$f(3)=(3)^3+2(3)^2-3=27+18-3=27+15=42$

$f(-3)=(-3)^3+2(-3)^2-3=(-27)+18-3=(-27)+15=(-12)$

Espero te sirva, saludos!