Question

b. (1/5 + 7/5 + 3/5) – (6/11-2/11)=​

Answer 1

Respuesta:

el resultado es $\frac{101}{55}=1\frac{46}{55}$

Explicación paso a paso:

$(\frac{1}{5} +\frac{7}{5} +\frac{3}{5} )-(\frac{6}{11} -\frac{2}{11} )\\\\(\frac{8}{5} +\frac{3}{5} )-(\frac{4}{11} )\\\\(\frac{11}{5} )-\frac{4}{11} \\\\\\\frac{11}{5}-\frac{4}{11} \\\\\frac{11}{5}-\frac{4}{11} \\\\\frac{101}{55} =1\frac{46}{55}$

Answer 2

ΗΘΙΑ

procedimiento :

$\frac{1}{5} +\frac{7}{5} +\frac{3}{5} -(\frac{6}{11} -\frac{2}{11} )$

$=\frac{8}{5} +\frac{3}{5} -(\frac{6}{11} -\frac{2}{11} )$

$=\frac{11}{5} -(\frac{6}{11} -\frac{2}{11} )$

$=\frac{11}{5} -\frac{4}{11}$

$=\frac{101}{55}$

salu2!!