Matemáticas, pregunta formulada por yerikjosua, hace 7 meses

ayuudaaaaaaa rapido porfa

Adjuntos:

Respuestas a la pregunta

Contestado por jane3345
1

Respuesta:

3(x - 1) - 2(x + 3) = 0 \\ 3x - 3 - 2x + 6 = 0 \\ 3x - 2x = 0 + 3 + 6 \\ x = 9

Explicación paso a paso:

b.

7(w + 20) - w = 5 \\ 7w + 140 - w = 5 \\ 7w - w = 5 - 140 \\ 6w =  - 135 \\ w =  - 135 \div 6 \\ w =  - 22.5

c.

9(x - 2) = 3x + 3 \\ 9x -  18 = 3x + 3 \\ 9x - 3x = 3 + 18 \\ 6x = 21 \\ x = 21 \div 6 \\ x = 3.5

d.

2(5a -  \frac{1}{3} ) =  \frac{2}{7}  \\ \\ 10a -  \frac{2}{3}  =  \frac{2}{7}  \\ 10a =  \frac{2}{7}  +  \frac{2}{3}  \\ 10a =  \frac{20}{21} \\a =  \frac{20}{21}  \div  \frac{1}{10}  \\ a =  \frac{200}{21}

e.

 \frac{2}{9} (i +  \frac{2}{3} ) =  \frac{2}{5}  \\  \frac{2i}{9}  +  \frac{4}{27}  =  \frac{2}{5} \\  \frac{2i}{9}  =  \frac{2}{5}  -  \frac{4}{27}   \\  \frac{2i}{9}  =  \frac{34}{135} \\ 2i =  \frac{34}{135}  \times 9 \\ 2i =  \frac{306}{135} \\ 2i =  \frac{34}{15} \\ i =  \frac{34}{15}  \div  \frac{1}{2}  \\ i =  \frac{68}{15}

f.

4(v +  \frac{1}{4} ) = \frac{35}{2}  \\ 4v +  \frac{4}{4}  =  \frac{35}{2}  \\ 4v + 1 = \frac{35}{2}  \\ 4v =  \frac{35}{2}  - 1 \\ 4v =  \frac{33}{2}  \\ v =  \frac{33}{4}  \div  \frac{1}{4}  \\ v =  \frac{132}{4}  = 33

g.

 \frac{s - 4}{11}  =  \frac{2}{5} \\ s - 4 =  \frac{2}{5}   \times 11 \\ s - 4 =  \frac{22}{5}  \\ s =  \frac{22}{5}  + 4 \\ s =  \frac{42}{5}

h.

 \frac{p}{10}  -  \frac{2p}{3}  =  \frac{1}{9} \\  \frac{3p - 12p}{30}  =  \frac{1}{9}  \\  \frac{ - 9p}{30}  =  \frac{1}{9}  \\  - 9p =  \frac{1}{9}  \times 30 \\  - 9p =  \frac{30}{9}  \\ p =  \frac{30}{9}  + 9 \\ p =  \frac{110}{9}


yerikjosua: gracias
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