Question

Ayudenmeeeee por faaaaa

Answer 1

Recuerda que:

$\sin(x) = \cos(90 - x)$

$\tan(x) = \cot(90 - x)$

$\tan(x) \times \cot(x) = 1$

...

A partir del dato tenemos:

$\beta + \alpha =90 - o \\ o + \beta = 90 - \alpha \\ o + \alpha = 90 - \beta$

Reemplazando en J:

$J = \frac{ \sin(90 - \beta ) }{ \cos( \beta ) } + \frac{ \tan( \alpha ) }{ \cot(90 - \alpha ) } + 7( \tan(90 - \beta ) \times \tan( \beta ) \\ J = \frac{ \cos( \beta ) }{ \cos( \beta ) } + \frac{ \tan( \alpha ) }{ \tan( \alpha ) } + 7 \cot( \beta ) \times \tan( \beta ) \\ J = 1 + 1 + 7 \\ J = 9$