Question

ayudenmeee porfaaaa respuestas correctas

Answer 1

TEMA: CONVERSIÓNES DE TEMPERATURA

→ ¿CÓMO COVERTIMOS UNIDADES DE TEMPERATURA ENTRE ELLAS?

           $\Huge\boxed{\boxed{\mathbf{\frac{C}{5}=\frac{F-32}{9}=\frac{K-273}{5}}}}$

Donde:

• C: Grados celsius
• F: Grados farenheit
• K: Grados kelvin

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$\mathbb{RESOLVEMOS!!}$

$\LARGE\boxed{\bigstar~\mathbf{18^oC~a~^oF}}$

Vamos a reemplazar el 18° en lugar de C y lo igualamos

$\mathbf{\frac{C}{5}=\frac{F-32}{9}}}}\\\\\mathbf{\frac{18}{5}=\frac{F-32}{9}}}}\\\\\mathbf{Multiplicamos~en~aspa}\\\\\mathbf{18 \times 9=5(F-32)}}}\\\\\mathbf{162=5F-160}}}\\\\\mathbf{162+160=5F}}}\\\\\mathbf{322=5F}}}\\\\\Large\boxed{\mathbf{F=64.4}}}$

RPTA: 18℃ = 64.4℉

$\LARGE\boxed{\bigstar~\mathbf{85^oF~a~^oC}}$

Vamos a reemplazar 85° en lugar de F y lo igualamos.

$\mathbf{\frac{F-32}{9}=\frac{C}{5}}}}\\\\\mathbf{\frac{53}{9}=\frac{C}{5}}}}\\\\\mathbf{Multiplicamos~en~aspa}}}\\\\\mathbf{53 \times 5=9C}\\\\\mathbf{265=9C}\\\\\Large\boxed{\mathbf{C=29.4}}$

RPTA: 85℉ = 29.4℃

$\LARGE\boxed{\bigstar~\mathbf{32^oC~a~^oK}}$

Hacemos lo mismo en todos los ejercicios así que omito la parte de la explicación.

$\mathbf{\frac{C}{5}=\frac{K-273}{5}}}}\\\\\mathbf{\frac{32}{5}=\frac{K-273}{5}}}}\\\\\mathbf{Se~simplifican~los~5~que~estan~de~denominadores}}}\\\\\mathbf{32=K-273}}}\\\\\Large \boxed{\mathbf{K=305}}}$

RPTA: 32℃ = 305 °K

$\LARGE\boxed{\bigstar~\mathbf{105^oF~a~^oK}}$

$\mathbf{\frac{F-32}{9}=\frac{K-273}{5}}}\\\\\mathbf{\frac{105-32}{9}=\frac{K-273}{5}}}\\\\\mathbf{\frac{73}{9}=\frac{K-273}{5}}}\\\\\mathbf{Multiplicamos~en~aspa}}\\\\\mathbf{73 \times 5 = 9(K-273)}}\\\\\mathbf{365= 9K-2457}}\\\\\mathbf{2822= 9K}}\\\\\Large\boxed{\mathbf{K=313.5}}}$

RPTA: 105℉ = 313.5°K

$\LARGE\boxed{\bigstar~\mathbf{589^oK~a~^oC}}$

$\mathbf{\frac{K-273}{5}=\frac{C}{5}}}}\\\\\mathbf{\frac{589-273}{5}=\frac{C}{5}}}}\\\\\mathbf{\frac{316}{5}=\frac{C}{5}}}}\\\\\mathbf{Eliminamos~los~5~de~los~denominadores}}}}\\\\\Large\boxed{\mathbf{316=C}}}$

RPTA: 589°K = 316℃

$\LARGE\boxed{\bigstar~\mathbf{315^oK~a~^oF}}$

$\mathbf{\frac{K-273}{5}=\frac{F-32}{9}}}}\\\\\mathbf{\frac{315-273}{5}=\frac{F-32}{9}}}}\\\\\mathbf{\frac{42}{5}=\frac{F-32}{9}}}}\\\\\mathbf{Multiplicamos~en~aspa}}}\\\\\mathbf{42 \times 9 = 5(F-32)}}}\\\\\mathbf{378 = 5F-160}}}\\\\\mathbf{538 = 5F}}}\\\\\Large\boxed{\mathbf{F=107.6}}}$

RPTA: 315°K = 107.6℉

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