Question

ayudenme :

realizar el cálculo porcentual de las siguientes fórmulas:


a) C6H12O6


b) H3PO4


c) K2 CR2 O7




ayudenme plis. :"3​

Answer 1

Explicación:

a- C6H12O6 --> 180 g/mol

C--> 12 g/mol; 12*6 =72 g/mol; 72/180 = 0.4 -->40%

H--> 1 g/mol; 1* 12 = 12 g/mol; 12/180 = 0.07 --> 7%

O--> 16 g/mol; 16*6 = 96 g/mol; 96/180 = 0.53 --> 53%

b- H3PO4 --> 98 g/mol

H--> 1 g/mol; 1*3 = 3 g/mol; 3/98 = 0.03 --> 3%

P--> 31 g/mol; 31*1 = 31 g/mol; 31/98 = 0.32 --> 32%

O--> 16 g/mol; 16*4 = 64 g/mol;  64/98 = 0.65 --> 65%

c- K2Cr2O7 --> 294 g/mol

K--> 39g/mol; 39*2 = 78 g/mol; 78/294 = 0.27 --> 27%

Cr--> 52 g/mol; 52*2 =  104 g/mol; 104/294 = 0.35 --> 35%

O--> 16 g/mol; 16*7 =112 g/mol; 112/294 = 0.38 --> 38%