Question

ayudenme porfavorrrr ‍♂️‍♂️​

Answer 1

a) tenemos que hallar el otro cateto

$c = \sqrt{( {52}^{2} ) - ( {20}^{2}) } = \sqrt{2304} = 48$

Cos= 20/52 = 10/21

Sen= 48/52 = 24/26 = 12/13

Tan = 48/20 = 24/10=12/5

b)

Tenemos que hallar la hipotenusa

$\sqrt{{3}^{2} + {4}^{2} } = \sqrt{25} = 5$

Sec = 1/cos =

Cos = 4/5. ➜ Sec = 5/4

Cosc = 1/ Sen

Sen = 3/5

Cosc ➜ 5/3

......... Kd