Question

AYUDENME PORFAVOR ES URGENTE SE LOS RUEGO AYUDENMEEEEEEEEEEEEEE

Answer 1

$P(x)=2x^{3}+4x^{2} -3 \\ \\ P(0)=2(0)^{3}+4(0)^{2} -3 \quad \to P(0)= 0+0-3 \to \boxed{P(0)= -3} \\ \\ P(-1)=2(-1)^{3}+4(-1)^{2} -3 \to P(-1)= -2+4-3 \to \boxed{P(-1)= -1} \\ \\ P( \sqrt{2})=2( \sqrt{2})^{3}+4( \sqrt{2})^{2} -3 \\ \to P( \sqrt{2} )=4 \sqrt{2}+8-3\qquad \to \boxed{P( \sqrt{2})=4 \sqrt{2}+5}$

$N(x)=17-8x^{2}-x^{3} \\ \\ N(-1)=17-8(-1)^{2}-(-1)^{3} \to N(-1)=17-8+1\to \boxed{N(-1)=10} \\ \\ N(N(-1))=17-8(10)^{2}-(10)^{3} \to N(N(-1))=17-800-1000 \to\\ \\ N( N(-1))=17-1800\to \boxed{N(N(-1))=-1783}$

$R(x)=5x^{2}- \frac{1}{2}x +4 \\ \\ \\ R(3)=5(3)^{2}- \frac{1}{2}(3) +4\quad \to R(3)=5(9)- \frac{3}{2} +4 \\ \\ R(3)=45- \frac{3}{2} +4 \to R(3)= \frac{90-3+8}{2} \to \boxed{ R(3)= \frac{95}{2} } \\ \\ \\ R(6)=5(6)^{2}- \frac{1}{2}(6) +4\quad \to R(6)=5(36)- \frac{6}{2} +4 \\ \\ R(6)=180-3 +4 \to R(6)= 180+1 \to \boxed{ R(6)= 181 } \\ \\ \\ \\ R( \pi )=5( \pi )^{2}- \frac{1}{2}( \pi ) +4\quad \to \boxed{ R( \pi )=5 \pi^{2}- \frac{ \pi }{2} +4 }$

$Q( x)= \sqrt{3} x^{4} - x^{2} \\ \\ Q( \sqrt{3})= \sqrt{3} ( \sqrt{3})^{4} -( \sqrt{3})^{2} \quad\to Q( \sqrt{3})= \sqrt{3} (9) -3 \\ \boxed{ Q( \sqrt{3})= 9\sqrt{3} -3 } \\ \\ \\ Q( 0)= \sqrt{3} (0)^{4} -(0)^{2} \quad\to Q( 0)= 0 -0 \\ \boxed{ Q( 0)= 0 } \\ \\ \\ Q(1)= \sqrt{3} (1)^{4} -(1)^{2} \quad\to \boxed{ Q( 1)= \sqrt{3} -1 }$

Espero que te sirva, salu2!!!!