Question

ayudenme porfavor :(

Answer 1

$p {b}^{2} = a {p}^{2} + a {b}^{2} \\ \\ p {b}^{2} = (6 \sqrt{3} {)}^{2} + {6}^{2} \\ \\ p {b}^{2} = 144 \\ \\ pb = 12$

$p {c}^{2} = p {b}^{2} + b {c}^{2} \\ \\ p {c}^{2} = 1 {2}^{2} + {5}^{2} \\ \\ p {c}^{2} = 169 \\ \\ pc = {\boxed{ { { \bold{{13}}}}}}$

${\boxed{ { { \bold{{Respuesta:13}}}}}}$

Espero haberte ayudado. :)