Question

AYUDENME PORFA, ES PARA HOY
DOY CORONITA Y CORAZÓN:)​

Answer 1

Respuesta:

a) x = -1/15

b) x = -15/4 Para comprobar, separa -> 2/3 * -15/4 = -30/12 = -10/4 = -5/2 mientras luego lo haces

c) x = 3

d) x₁ = -5/3

x₂ = 7

Explicación paso a paso:

Ecuaciones

a) $x+\frac{2}{5} =\frac{1}{3}$

$x =\frac{1}{3} -\frac{2}{5}$

$15x/15 =\frac{5}{15} -\frac{6}{15}$

$15x =5 - 6$

$15x = -1$

$x = -1/15$

b) $\frac{2x}{3} -\frac{1}{2} = x + \frac{3}{4}$

$\frac{8x}{12} -\frac{6}{12} = 12x/12 + \frac{9}{12}$

$8x - 6 = 12x + 9$

$8x - 12x = 9 + 6$

$-4x = 15$

$x = -15/4$

c) $(\frac{2}{x})^{7} = \frac{128}{2187}$

$\frac{2}{x} = \sqrt{\frac{128}{2187}$

$\frac{2}{x} = \frac{\sqrt{128} }{\sqrt{2187} }$

$\frac{2}{x} = \frac{\sqrt[7]{128} }{\sqrt[7]{2187} }$

$\frac{2}{x} = \frac{2}{3}$

$2 = \frac{2}{3}*x$

$2*3 = 2*x$

$6/2 = x$

$3 = x$

d) $\frac{35}{x} +15 = 3x -1$

$\frac{35}{x} = 3x -1 - 15$

$35 = x(3x -16)$

$35 = 3x^{2} -16x$

$0 = 3x^{2} -16x - 35$

$-3x^{2} +16x + 35 = 0$

$x = \frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}$

$x = \frac{-16+-\sqrt{16^{2}-4*(-3)*35 } }{2*(-3)}$

$x = \frac{-16+-\sqrt{256-(-12)*35 } }{-6}$

$x = \frac{-16+-\sqrt{256-(-420) } }{-6}$

$x = \frac{-16+-\sqrt{256+420 } }{-6}$

$x = \frac{-16+-\sqrt{676 } }{-6}$

$x_1 = \frac{-16+\sqrt{676 } }{-6} = \frac{-16+26}{-6} = \frac{10}{-6} = \frac{-5}{3}$

$x_2 = \frac{-16-\sqrt{676 } }{-6} = \frac{-16-26}{-6} = \frac{-42}{-6} = 7$