Question

ayúdenme por favor
(p - 1) · x² - px + 7 - 3x² = x² - 2x + p

Answer 1

Respuesta:

Alternate forms:

p (x - 1) x + 7 = p + x (5 x - 2)

p (x - 1) x - 4 x^2 + 7 = p + (x - 2) x

p (x^2 - x - 1) = 5 x^2 - 2 x - 7

Expanded forms:

p x^2 - p x - 4 x^2 + 7 = p + x^2 - 2 x

p x^2 - p x - p - 5 x^2 + 2 x + 7 = 0

Solutions:

p - 5!=0, x = (-sqrt(5 p^2 - 52 p + 144) + p - 2)/(2 (p - 5))

p - 5!=0, x = (sqrt(5 p^2 - 52 p + 144) + p - 2)/(2 (p - 5))

Solution:

p = 5, x = 2/3

Integer solutions:

x = -3, p = 4

x = -1, p = 0

x = 0, p = 7

x = 1, p = 4

x = 2, p = 9

Implicit derivatives:

(dx(p))/(dp) = (1 + x - x^2)/(2 - p - 10 x + 2 p x)

(dp(x))/(dx) = (-2 + p + 10 x - 2 p x)/(-1 - x + x^2)

Espero te sirva :)