Question

Ayudenme por favor es urgente.​

Answer 1

Explicación paso a paso:

1).

${( \sqrt{5 + \sqrt{24}} - \sqrt{5 - \sqrt{24} } )}^{2}$

${( \sqrt{5 + \sqrt{ {2}^{2} \times 6 }} - \sqrt{5 - \sqrt{ {2}^{2} \times 6} } )}^{2}$

${( \sqrt{5 + 2 \sqrt{6}} - \sqrt{5 - 2 \sqrt{6} } )}^{2}$

${( \sqrt{ {( \sqrt{2} + \sqrt{3}) }^{2} } - \sqrt{ {( \sqrt{2} - \sqrt{3} )}^{2} } )}^{2}$

${( \sqrt{2} + \sqrt{3} - ( \sqrt{3} - \sqrt{2}))}^{2}$

${(2 \sqrt{2}})^{2}$

R = 4•2 = 8

2).

$\frac{{(x - y)}^{3} + {(y - z)}^{3} + {(x - z)}^{3}}{5}$

x - y = y - z = 1

como y - z = 1; despejando z: z = y - 1

entonces:

$\frac{{1}^{3} + {1}^{3} + {(x - (y - 1))}^{3}}{5}$

$\frac{1 + 1 + {(1 + 1)}^{3} }{5}$

$\frac{10}{5} = 2$

B = 2

3).

E = (x + y)² + (x - y)² + 2(x² + y²)

Dónde x = 2√3 ; y = 3√2

E = (x²+2xy+y²) + (x²-2xy+y²) + 2x² + 2y²

E = 2x² + 2y² + 2x² + 2y²

E = 4x² + 4y²

E = 4(2√3)² + 4(3√2)²

E = 4(4•3) + 4(9•2)

E = 48 + 72

E = 120

4).

M = (x-1)(x+2)+(x-3)(x+6)-2(x+1)²

M = (x²-x+2x-2)+(x²-3x+6x-18)-2(x²+2x+1)

M = x²+x-2+x²+3x-18-2x²-4x-2

M = 2x²+4x-20-2x²-4x-2

M = -22