Question

Ayúdenme pls con la 2, 3 o 4

Answer 1

Respuesta:

x = { -3; 2}

Explicación paso a paso:

$\frac{x+1}{x-1} + \frac{x}{2} = x +2$

$\frac{2*(x+1)+x*(x-1)}{2*(x-1)} = x +2$

$2*(x+1)+x*(x-1)} = (x +2)*2*(x -1 )$

$2*x+2+x^{2} -x = 2*(x^{2} + 2*x - x +2*(-1) )$

$x^{2}+x+2 = 2*(x^{2} + x -2)$

$x^{2}+x+2 = 2*x^{2} + 2*x - 4$

$0 = 2*x^{2} - x^{2} + 2*x -x - 4 -2$

$0 = x^{2} + x - 6$

      x           +3

      x           -2 = (3*x) - (2*x) = x (cumple)

$0 = (x+3)*(x -2)$

Se cumple que:

x + 3 = 0     ; x - 2 = 0

x = -3          ;  x = 2

Por lo tanto: x = { -3; 2}