Matemáticas, pregunta formulada por yaretzinicol9, hace 10 meses

Ayúdenme es para hoy

a) (4x+6)(14x-10)
b)
(6x - 8y^{2})(4x^{3} - 12 {x}^{2}y + 14 {y}^{4})
c) (w+6)(4w-10)(12w-2)
d) (1+1)(10.5+4)​

Respuestas a la pregunta

Contestado por lulu120615
1

Respuesta:

A) 56x²+44x-60

B)24x^4 - 72x^3y + 84xy^4 - 32x^3y² + 96x² - 112y^6

C)48w³+160w²-788w+120

D)29

Explicación paso a paso:

A)

(4x)(14x)+(4x)(-10)+(6)(14x)+(6)(-10) = 56x²-40x+84x-60 = 56x²+44x-60

B)

(6x)(4x³)+(6x)(-12x²y)+(6x)(14y^4) + (-8y²)(4x³) + (-8y²)(-12x²y)+(-8y²)(14y^4) =

24x^4 - 72x³y + 84xy^4 - 32x³y² + 96x² - 112y^6

C)

((w)(4w)+(w)(-10)+(6)(4w)+(6)(-10))(12w-2)

(4w²-10w+24w-60)(12w-2)=

(4w²)(12w)+(4w²)(-2)+(-10w)(12w)+(10w)(-2)+(24w)(12w)+(24w)(-2)+(-60)(12w)+(-60)(-2)=

48w³-8w²-120w²-20w+288w²-48w-720w+120=

48w³+160w²-788w+120

D)

(1+1)(10.5+4)= (2)(14.5)= 29

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