Question

ayudenme es de numeros imaginarios y complejos

Answer 1

$\frac{ {i}^{98} \times {i}^{1} }{ {i}^{92} } = \frac{ {i}^{99} }{ {i}^{92} } = {i}^{99 - 92} \\ = {i}^{7} = {i}^{3} = - i$
$( \frac{7}{2} - i) + (3 - \frac{1}{5}i) \\ = \frac{7}{2} - i + 3 - \frac{1}{5} i \\ = \frac{7 + 6}{2} - i(1 + \frac{1}{5} ) \\ = \frac{13}{2} - i \frac{5 + 1}{5} \\ \frac{13}{2} - i \frac{6}{5}$