Question

ayudenme en esto porfis ​

Answer 1

Respuesta:

1) $\sf{x _{1} = - 6 - 2 \sqrt{14} , x_{2} = - 6 + 2 \sqrt{14}}$

2) $\sf{ x_{1} = 3, x_{2} = 6 }$

Explicación paso a paso:

Resolvemos:

1)

$\sf0 = {x}^{2} + 12x - 20$

$\sf {x}^{2} + 12x - 20 = 0$

$\sf{x = \frac{ - 12 ± \sqrt{ {12}^{2} - 4 \times 1 \times ( - 20)} }{2 \times 1} }$

$\sf{x = \frac{ - 12 ± \sqrt{144 + 80} }{2} }$

$\sf{x = \frac{ - 12 ± \sqrt{224} }{2} }$

$\sf{x = \frac{ - 12 ± 4 \sqrt{14} }{2} }$

$\sf{x = \frac{ - 12 + 4 \sqrt{14} }{2} } \\ \sf{x = \frac{ - 12 - 4 \sqrt{14} }{2} }$

$\sf{x = - 6 + 2 \sqrt{14} } \\ \sf{x = - 6 - 2 \sqrt{14} }$

$\boxed{ \sf{x _{1} = - 6 - 2 \sqrt{14} , x_{2} = - 6 + 2 \sqrt{14} }}$

2)

$\sf{0 = {x}^{2} - 9x + 18}$

$\sf {x}^{2} - 9x + 18 = 0$

$\sf {x}^{2} - 3x - 6x + 18 = 0$

$\sf{x(x - 3) - 6(x - 3) = 0}$

$\sf(x - 3)(x - 6) = 0$

$\sf{x - 3 = 0} \\ \sf{x - 6 = 0}$

$\sf{x = 3} \\ \sf{x = 6}$

$\boxed{ \sf{ x_{1} = 3, x_{2} = 6 }}$

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