Question

Ayudenme en esta porfaaaa

Answer 1

1)

${n}^{2} - \frac{16}{25} = 0$

${n}^{2} = \frac{16}{25}$

$n = \sqrt{ \frac{16}{25} }$

$n = \frac{4}{5}$

2)

${(x - 1)}^{2} - 4 = 0$

${(x - 1)}^{2} = 4$

$x - 1 = \sqrt{4}$

$x - 1 = 2$

$x = 1 + 2$

$x = 3$

3)

${(m - 2)}^{2} - \frac{25}{4} = 0$

${(m - 2)}^{2} = \frac{25}{4}$

$m - 2 = \sqrt{ \frac{25}{4} }$

$m - 2 = \frac{5}{2}$

$m = \frac{5}{2} + 2$

$m = \frac{9}{2}$