Question

ayúdenme, daré Corona a la mejor respuesta (con su procedimiento).​

Answer 1

Respuesta:

a) 3x + 38 =101

3x = 101 -38

3x = 63

x = 63/3

x = 21

b)4x+1=x+4

4x-x = 4-1

3x = 3

x= 3/3 = 1

c)5x + 3^(2) = 2^(4)

5x + 9 = 16

5x = 16-9

5x = 7

x=7/5

d)

$\frac{6x-2}{4} =\sqrt{169} \\\frac{2(3x-1)}{4} =13 \\\frac{(3x-1)}{2} =13 \\3x-1=13*2\\ 3x-1=26\\3x=26+1\\3x =27\\x=\frac{27}{3} \\x=9$

f)5x-4 = 3 -2x

5x + 2x = 3 + 4

7x = 7

x = 7/7 = 1

g) 2x - 4 = 5 - x

2x +x = 5 + 4

3x = 6

x = 6/3 = 2

h) 5 (x + 2) - 8 = 4 (x + 2) -1

5 (x + 2) - 4 (x + 2) = -1 + 8

(5 - 4)(x + 2) = 9

3 (x + 2) = 9

x + 2 = 9/3

x + 2 = 3

x = 3-2 = 1

j)

$\frac{x-5}{x+5} =\frac{6}{7} \\\\7(x-5) = 6(x+5)\\7x - 35 = 6x + 30\\7x - 6x = 30 + 35\\x = 65$