Question

Ayúdenme con estos 10 ejercicios, plis es para mañana
(5p^5+3q^6)^2

(6b^3+5c^4)^2

(7rs^3+5tu^3)^2

(9p^3+9m^3)^2

(2x^7+3y^12)^2

(2d^5–3fg^2)^2

(4a^7–b^5)^2

(12m^3–13n^4)^2

(10f^3–9gh^5)^2

(8x^6–y^7)^2

4134147e98a16cfcc477fdaead6d7e26.docx

Answer 1

Explicación paso a paso:

Binomio al  cuadrado:

(a ± b)² = a² ± 2ab + b²

(5p⁵+3q⁶)² = (5p⁵)²+2(5p⁵)(3q⁶)+(3q⁶)²

(5p⁵+3q⁶)² = 25p¹⁰+30p⁵q⁶+9q¹²

(

6b³+5c⁴)² = (6b³)²+2(6b³)(5c⁴)+(5c⁴)²  

(6b³+5c⁴)² = 36b⁶+60b³c⁴+25c⁸  

(7rs³+5tu³)² = (7rs³)²+2(7rs³)(5tu³)+(5tu³)²

(7rs³+5tu³)² = 49r²s⁶+70rs³tu³+25t²u⁶

(9p³+9m³)² = (9p³)²+2(9p³)(9m³)+(9m³)²

(9p³+9m³)² = 81p⁶+162p³m³+81m⁶

(2x⁷+3y¹²)² = (2x⁷)²+2(2x⁷)(3y¹²)+(3y¹²)²

(2x⁷+3y¹²)² = 4x¹⁴+12x⁷y¹²+9y²⁴

(2d⁵-3fg²)² = (2d⁵)²-2(2d⁵)(3fg²)+(3fg²)²

(2d⁵-3fg²)² = 4d¹⁰-12d⁵fg²+9f²g⁴

(4a⁷-b⁵)² = (4a⁷)²-2(4a⁷)(b⁵)+(b⁵)²  

(4a⁷-b⁵)² = 16a¹⁴-8a⁷b⁵+b¹⁰  

(12m³-13n⁴)² = (12m³)²-2(12m³)(13n⁴)+(13n⁴)²

(12m³-13n⁴)² = 144m⁶-312m³n⁴+169n⁸

(10f³-9gh⁵)² = (10f³)²-2(10f³)(9gh⁵)+(9gh⁵)²

(10f³-9h⁵)² = 100f⁶-180f³gh⁵+81g²h¹⁰

(8x⁶-y⁷)² = (8x⁶)²-2(8x⁶)(y⁷)+(y⁷)²

(8x⁶-y⁷)² = 64x¹²-16x⁶y⁷+y¹⁴