Question

AYUDENME CON ESTO POR FAVOR ES URGENTE!!!

Answer 1

a)$\frac{2^4 * 2^3 * 2^7}{2^5 * 2^6} =\frac{2^4+^3+^7}{2^5+^6} = \frac{2^1^4}{2^1^1} = 2^1^4-2^1^1=2^3$

b) $\frac{x^3 * (x^4)^2}{x^6*x*x^2} =\frac{x^3+^8}{x^6+^1+^2} = \frac{x^1^1}{x^8} =x^1^1-^8=x^3$

c)$\frac{(-5)^3*((-5)^2)^5}{((-5)^3)^4*(-5)} =\frac{(-5)^3+^1^0}{(-5)^1^2+^1}=\frac{(-5)^1^3}{(-5)^1^3} = (-5)^1^3-^1^3=(-5)^0=1$