Question

ayudenme con esto por favor​

Answer 1

Holaaaaaaa:

2 si:

$x + \frac{1}{x} = 3$

$(x + \frac{1}{x} ) = {3}^{2}$

${x}^{2} + 2.x .\frac{1}{x} + \frac{1}{ {x}^{2} } = 9$

${x}^{2} + 2.1+ \frac{1}{ {x}^{2} } = 9$

${x}^{2} + 2+ \frac{1}{ {x}^{2} } = 9$

${x}^{2} + \frac{1}{ {x}^{2} } = 9 - 2$

${x}^{2} + \frac{1}{ {x}^{2} } = 7$

3. a+b=6

a·b = 7

$(a + b)^{2} = {a}^{2} + 2ab + {b}^{2}$

$(6)^{2} = {a}^{2} + 2(7) + {b}^{2}$

$36 = {a}^{2} + 14+ {b}^{2}$

$36 - 14 = {a}^{2} + {b}^{2}$

$22 = {a}^{2} + {b}^{2}$