Question

Ayudenme con esto please

Answer 1

Hola!

Explicación paso a paso:

2)

$Area_{sombreada}=\pi \times {(4 \: cm)}^{2} - \pi \times {(2 \: cm)}^{2}\\Area_{sombreada} = 16\pi \: {cm}^{2} - 4\pi \: {cm}^{2} \\ Area_{sombreada} = 12\pi \: {cm}^{2}$

3)

$Area_{sombreada}=\pi \times {(7 \: cm)}^{2} - \pi \times {(4 \: cm)}^{2}\\Area_{sombreada} = 49\pi \: {cm}^{2} - 16\pi \: {cm}^{2} \\ Area_{sombreada} = 33\pi \: {cm}^{2}$

4)

$Area_{sombreada}= \frac{\pi \times {(8 \: cm)}^{2}}{2}\\Area_{sombreada} = \frac{ 64\pi \: {cm}^{2} }{2} \\ Area_{sombreada} = 32\pi \: {cm}^{2}$

6)

$Area_{sombreada}= \frac{\pi \times {(8 \: cm)}^{2} }{4} - \frac{\pi \times {(4\: cm)}^{2}}{2}\\Area_{sombreada} = 16\pi \: {cm}^{2} - 8\pi \: {cm}^{2} \\ Area_{sombreada} = 8\pi \: {cm}^{2}$

7)

$Area_{sombreada}= </strong><strong>\pi \times {(</strong><strong>6</strong><strong> \: cm)}^{2}</strong><strong> - \frac{</strong><strong>\pi \times {(6 \: cm)}^{2}</strong><strong>}{</strong><strong>6</strong><strong>}\\Area_{sombreada} = </strong><strong>3</strong><strong>6</strong><strong>\pi \: {cm}^{2} - </strong><strong>6</strong><strong>\pi \: {cm}^{2} \\ Area_{sombreada} = </strong><strong>3</strong><strong>0</strong><strong>\pi \: {cm}^{2}$

8)

$Area_{sombreada}= </strong><strong>\pi \times {(</strong><strong>6</strong><strong> </strong><strong>\: cm)}^{2} </strong><strong>- \frac{\pi \times {(</strong><strong>6</strong><strong>\: cm)}^{2}}{</strong><strong>3</strong><strong>}\\Area_{sombreada} = </strong><strong>3</strong><strong>6</strong><strong>\pi \: {cm}^{2} - </strong><strong>1</strong><strong>2</strong><strong>\pi \: {cm}^{2} \\ Area_{sombreada} = </strong><strong>2</strong><strong>4</strong><strong>\pi \: {cm}^{2}$

Ojo: No hay alternativa, debe ser que la sombreaste mal!