Historia, pregunta formulada por odethjohan, hace 8 meses

Ayudenme con este solo ejercicio PLISS le dio corona el que me de la respuesta
2x²-2y²/ ³√x+y

Respuestas a la pregunta

Contestado por samibelmontemaita
0

Respuesta:

In both cases, use the linear equation to express one variable in terms of the other, and then substitute the dependent variable in the quadratic equation. This will give you a quadratic equation in one variable which you solve with the quadratic formula. I’ll do the first part of #1 for you, and then you can do the rest on your own.

x=3+2y , so, substituting,

(3+2y)2+2y2=27  

9+12y+4y2+2y2=27  

9+12y+6y2=27  

3+4y+2y2=9  

2y2+4y−6=0  

y2+2y−3=0  

Just remember the quadratic formula: for any variable  x , any constants  a,b,c , where  ax2+bx+c=0 ,

x=−b±b2−4ac√2a  

And plug it in, and solve for  y . You can then use the linear equation with a known value of  y  to solve for  x .

Explicación:


odethjohan: Es correcto ??
Otras preguntas