Question

Ayudenme con estas potencias:

$\frac{3 { - }^{2} }{9 } =$
$( {99}^{0} - {23.4)}^{2} =$
${10}^{2} \times {10}^{3} =$
$\frac{ - {3}^{0} }{( {3)}^{2} } =$

Answer 1

$\frac{3 ^{-2} }{9} = \frac{3^{-2} }{3^{2} } = 3^{-2-2} = 3^{-4} = \frac{1}{ 3^{4} } = \frac{1}{81}$

$(99^{0}-23.4)^{2} = (1-92)^{2} = (-91)^{2} = 8281$

$10^{2} .10^{3} = 10^{2+3} = 10^{5} = 100 000$


$\frac{-3^{0}}{3 ^{2} } = \frac{-1}{9}$